确定什么被氧化或被还原-概念

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年代 So that means that Oxidation lose electrons; LEO. Loss electrons oxidation. Then GER; gain electrons, R, reduction.



O That also means that the oxidation number would increase. Reduction just like it says, the oxidation number would decrease. If you need help with oxidation numbers, we also have another video that will help you in figuring out oxidation numbers.



T So it's a reactant that is causing the other thing to be reduced. Just like an agent helps a ball player negotiate a contract, basically the reducing agent, is the thing that's being oxidized. It's causing the other thing to be reduced. Then also, the thing that's being reduced, is also known as the oxidizing agent.



年代 So I'll show you two methods. We have Na+Cl2 yields NaCl. This would be easy to balance, because you would put the 2 there, and a 2 there. But here is two methods that you use to figure this out.



年代 The oxidation number of the Chlorine, since it's by itself is also 0. Then the oxidation number of Sodium on the product in the NaCl is +1. The oxidation number of Chloride is -1, because those are charges. So this is the oxidation number.



年代 Well, the oxidation number went up by 1. Then we take a look at the Chlorine, what happened? Well, the oxidation number went down by 1. So what happens is, what gets oxidized? Well, the one and where the base number goes up. So that would be the Sodium in this case, Na.



t Well, that's the Chlorine would happen. So which one gained electrons? Well, the one that got reduced gained the electrons, so that would be the Chlorine. Chlorine gained electrons. Then that means that the Sodium had to lose electrons. So if you gain electrons, you lose electrons, then you can also figure that out too.



年代 Then the Cl2 becomes the Cl- in that ion. So if you take a look at what happens, well, gain of electrons, loss of electrons as well. Since I have 0charge on the left side for the Sodium, I have +1 on the right side, that means I need to add one electron here, to make the charges equal for the sodium.



年代 So that's oxidation. Then for Cl2, you balance it. So you have 2 Chlorines. So you add 2 electrons here to the reactant side. So basically you're gaining electrons, which means that you're having reduction.



年代 Or you can take a look at what's happening to the electrons like we did below, to figure out if something is being oxidized or reduced. You can do these with any Redox equation, because where there's oxidation, there always has to be reduction. You can't have oxidation and oxidation, or reduction and reduction. You have to have oxidations with reduction, because you have to have a lose of electrons, along with a gain of electrons. The electrons have to go somewhere.



年代 Have a good one.